用Java语言将一个键盘输入的数字转化成中文输出
2023-06-29
(例如:输入:1234567 输出:一百二拾三万四千五百六拾七)
用java语言实现,,请编一段程序实现!
1. public class Reader
2. private String strNum;
3.
4. private String strNumChFormat;
5.
6. private String strNumTemp;
7.
8. private int intNumLen;
9.
10. private String strBegin;
11.
12. public Reader(String strNum)
13. this.strNum = strNum;
14.
15.
16. public boolean check(String strNum)
17. boolean valid = false;
18. if (strNum.substring(0, 1).equals(“0″))
19. this.strNum = strNum.substring(1);
20.
21. try
22. new Double(strNum);
23. valid = true;
24. catch (NumberFormatException ex)
25. System.out.println(“Bad number format!”);
26.
27. return valid;
28.
29.
30. public void init()
31. strNumChFormat = “”;
32. intNumLen = strNum.length();
33. strNumTemp = strNum;
34. strNumTemp = strNumTemp.replace(’1′, ‘一’);
35. strNumTemp = strNumTemp.replace(’2′, ‘二’);
36. strNumTemp = strNumTemp.replace(’3′, ‘三’);
37. strNumTemp = strNumTemp.replace(’4′, ‘四’);
38. strNumTemp = strNumTemp.replace(’5′, ‘五’);
39. strNumTemp = strNumTemp.replace(’6′, ‘六’);
40. strNumTemp = strNumTemp.replace(’7′, ‘七’);
41. strNumTemp = strNumTemp.replace(’8′, ‘八’);
42. strNumTemp = strNumTemp.replace(’9′, ‘九’);
43. strNumTemp = strNumTemp.replace(’0′, ‘零’);
44. strNumTemp = strNumTemp.replace(‘.’, ‘点’);
45. strBegin = strNumTemp.substring(0, 1);
46.
47.
48. public String readNum()
49. if (check(strNum))
50. init();
51. try
52. for (int i = 1, j = 1, k = 1; i < intNumLen; i++)
53. if (strNumTemp.charAt(intNumLen – 1) == ‘零’ && i == 1)
54. strNumChFormat = “位”;
55. else if (strNumTemp.charAt(intNumLen – i) == ‘零’ && j == 1)
56. strNumChFormat = “位” + strNumChFormat;
57. else if (strNumTemp.charAt(intNumLen – i) == ‘点’)
58. j = 1;
59. k = 1;
60. strNumChFormat = strNumTemp.charAt(intNumLen – i) + strNumChFormat;
61. continue;
62. else
63. strNumChFormat = strNumTemp.charAt(intNumLen – i) + strNumChFormat;
64.
65. if (strNumTemp.charAt(intNumLen – i – 1) != ‘位’ && strNumTemp.charAt(intNumLen – i – 1) != ‘零’)
66. if (j == 1 && i < intNumLen)
67. strNumChFormat = ‘拾’ + strNumChFormat;
68. else if (j == 2 && i < intNumLen)
69. strNumChFormat = ‘百’ + strNumChFormat;
70. else if (j == 3 && i < intNumLen)
71. strNumChFormat = ‘千’ + strNumChFormat;
72.
73.
74. if (j == 4 && i < intNumLen)
75. j = 0;
76.
77. if (k == 4 && i < intNumLen)
78. strNumChFormat = ‘万’ + strNumChFormat;
79. else if (k == 8 && i < intNumLen)
80. k = 0;
81. strNumChFormat = ‘亿’ + strNumChFormat;
82.
83. j++;
84. k++;
85.
86. while (strNumChFormat.indexOf(“位”) != -1)
87. strNumChFormat = strNumChFormat.replaceAll(“位”, ” “);
88.
89. if (strNumChFormat.substring(0, 2) == “一拾”)
90. strNumChFormat = strNumChFormat.substring(1, strNumChFormat.length());
91.
92. if (strNumChFormat.indexOf(“点”) >= 0)
93. String rebegin = strNumChFormat.substring(0, strNumChFormat.indexOf(“点”));
94. String relast = strNumChFormat.substring(strNumChFormat.indexOf(“点”), strNumChFormat.length());
95. for (int i = 1; i